Search for a column by name in awk

I have a file that has many columns. Let us say “Employee_number” “Employee_name” “Salary”. I want to display all entries in a column by giving all or part of the column name. For example if my input “name” I want all the employee names printed. Is it possible to do this in a simple manner using awk?
Thanks

Given a script getcol.awk as follows:

BEGIN {
    colname = ARGV[1]
    ARGV[1] = ""
    getline
    for (i = 1; i <= NF; i++) {
        if ($i ~ colname) {
            break;
        }
    }
    if (i > NF) exit
}

{print $i}

… and the input file test.txt:

apple   banana  candy   deer    elephant
A   B   C   D   E
A   B   C   D   E
A   B   C   D   E
A   B   C   D   E
A   B   C   D   E
A   B   C   D   E
A   B   C   D   E

… the command:

$ awk -f getcol.awk b <test.txt

… gives the following output:

B
B
B
B
B
B
B

Note that the output text does not include the first line of the test file, which is treated as a header.